x^2+2-25x-50=0

Solution for x^2+2-25x-50=0 equation:

x^2+2-25x-50=0

We add all the numbers together, and all the variables

x^2-25x-48=0

a = 1; b = -25; c = -48;
Δ = b2-4ac
Δ = -252-4·1·(-48)
Δ = 817
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-\sqrt{817}}{2*1}=\frac{25-\sqrt{817}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+\sqrt{817}}{2*1}=\frac{25+\sqrt{817}}{2}
$